Mr_Creepy said:
			
		
	
	
		
		
			Tony the reg does not stop you from going below the glide slope. Find me the reg that says you have to land at the aim point! Please!
		
		
	 
You must learn to focus better if we are to have an intelligent conversation here. Find me a reference to where I said anyone has to land at the aim point.
 
The argument that I have submitted is that one must remain at or above the glideslope, whether it is electronic (ILS) or visual. I have provided quotes from 14 CFR that support my position, save the interpretation of the MM inbound portion of the ILS, and the "necessary for safe landing" part of the visual.
 
That's where I posed the scenario of the 747 changing everything at the MM to land on the numbers - - how can he do it?
 
 
	
		
			
				Mr_Creepy said:
			
		
	
	
		
		
			I already answered this, but I'll do it again. Besides a 30kt tail wind, I just talked to one of my Polar pilot friends. Here is what they are taught.
		
		
	 
Is that your answer? 30kt 
head wind? (I'm assuming your tail wind here was a typo, based on your Post # 55)
 
OK. Let's talk geometry. A 3 degree descent gradient will have you lose 318 feet (round it to 300 if it makes you feel better) for every one NM travelled along the ground. 3 degrees in no wind is the same as 3 degrees in a tail wind is the same as 3 degrees in a head wind. If the wind is blowing at 100 knots off the nose, 3 degrees is still 3 degrees.
 
The geometry is independent of winds.  To phrase it another way, it doesn't matter what the winds are, a 3 degree descent gradient is still a 3 degree descent gradient.
 
Comparing a calm wind 3 degree descent with a light headwind 3 degree descent, the former will require less power, result in a slightly higher descent rate, and will require a very slightly higher deck angle than the latter. BOTH will have a STABLE power setting, STABLE deck angle, and STABLE descent rate. Both will require a deviation from that power setting, deck angle, and descent rate to achieve something MORE than a 3 degree descent gradient to land short of the previously stabilized point.
 
 
 
	
		
			
				Mr_Creepy said:
			
		
	
	
		
		
			They must cross the threshold at 47' AGL to avoid hitting any ILS equipment. So postulate a 300'/mile stabilzed descent +- 100' (or approx 1000fpm descent rate at 164 kts)
 
This equates to a no wind touch down point approximately 892 feet down the runway. Any headwind at all and they can land at 500 ft.
 
Hope this answers your question.
		
		
	 
 
Again - - and I'm glad you explained what you're thinking so we can really address the problem head on - - a stabilized descent at 300 ft per NM in ANY wind conditions will result in the exact same aim point. To follow your logic would mean that landing in a 50 knot headwind would result in landing short of the runway. That's simply not true.
 
 
 
	
		
			
				Mr_Creepy said:
			
		
	
	
		
		
			By the way - what equipment do you fly?
		
		
	 
 
 
I don't, I just stayed at a Holiday Inn Express once.
 
 
 
 
 
 
 
 
 
I fly the 727 currently. I have flown and instructed on the MD-11/MD-10. I flew RC-135's in the Air Force. We use the same concepts for the DC-10 and the A300. I used the same concepts in the T-37.
 
 
 
OK. So let me ask once more, and you're going to have to some up with a better answer than "30 kt head wind."
 
You're in your mighty 747 (care to guess how much inertia you're dealing with here?) and you're stable on a 3 degree glidepath. You have established a power setting, a deck angle, and a descent rate (VVI) that holds the glidepath perfectly. Now you're at the MM, 200' above the ground.
 
Exactly what will you do with the throttles, and the yoke, to make the airplane land, using normal descent rates and normal maneuvers, to change your descent gradient and land on the numbers?
 
Your copilot is the type that will say "Unstable, Go-Around" if he sees any parameter out of tolerance, so be careful. And please be specific.
 
 
 
 
 
 
 
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