Screaming_Emu
Well-Known Member
Don't ever be afraid to say unable or I can't accept that if you aren't comfortable doing so.
I wonder if that's a valid answer on the interview.
Don't ever be afraid to say unable or I can't accept that if you aren't comfortable doing so.
Uh, with radar monitoring, "fly heading (___) and direct Volunteer when able" is perfectly legal.
Direct to a radial-DME fix, not so solid.
You will eventually be able to go direct Volunteer on your own.That's what I was getting at. I know you can always take radar vectors, but if you can't navigate your way direct a VOR on your own outside the service area, how is that any different than trying to go direct some point in space without RNAV equipment?
You will eventually be able to go direct Volunteer on your own.
Yes you will eventually pick up the VOR, but when you can't, the only way legally to go direct is to take a vector. If you're not RNAV equipped, at what point would you pick up the radial/DME fix you're navigating to? Seems like a quick way to get a pilot deviation to me.
They can't give you the clearance to begin with if you aren't RNAV/IRU equipped. The FARs require you to report the loss of any required navigational equipment in flight if it happens so they wouldn't give you that clearance after that. If they give you a vector it will be something like "fly heading XXX and proceed direct XXX upon receiving."
They can't give you the clearance to begin with if you aren't RNAV/IRU equipped. The FARs require you to report the loss of any required navigational equipment in flight if it happens so they wouldn't give you that clearance after that. If they give you a vector it will be something like "fly heading XXX and proceed direct XXX upon receiving."
Yes you will eventually pick up the VOR, but when you can't, the only way legally to go direct is to take a vector. If you're not RNAV equipped, at what point would you pick up the radial/DME fix you're navigating to? Seems like a quick way to get a pilot deviation to me.
Situational awareness?Trust me, I know how this stuff works and the legality behind. The point I have been trying to make is, you can't use a pencil trick to go direct to a point in space, so why do I need to know it? But I guess that's how aviation works.
Here's one for you geniuses... How do you solve this? It's not in the mental math book unfortunately.
You are on the 090 radial at 20 DME. What heading would you fly to go direct to the 60 DME fix on the 190 radial of the same VOR?
Here's one for you geniuses... How do you solve this? It's not in the mental math book unfortunately.
You are on the 090 radial at 20 DME. What heading would you fly to go direct to the 60 DME fix on the 190 radial of the same VOR?
Are you saying that you can't fly to a VOR that you are not receiving when not equipped with RNAV?
Situational awareness?
Yes.
No idea how to do this mentally aside from just visualizing the picture and knowing that its between 190 and 210. But regardless heres the trig:
Pythagorean Theorm: A2 + B2 = C2
20^2 + 60^2 = 4000. SquareRoot(4000) = 63.25
![]()
At this point you can already tell the heading will be between 190 and 210ish.
Now you must solve for the angle that will give you the heading(or course).
![]()
Talking about a direct to clearance, not a charted airway.How would you fly an airway with a MEA Gap in a /A aircraft?
Pythagorean Theorem (on flat Euclidean geometry) only works for triangles where one of the angles is 90 degrees i.e. a right triangle:No idea how to do this mentally aside from just visualizing the picture and knowing that its between 190 and 210. But regardless heres the trig:
Pythagorean Theorm: A2 + B2 = C2
20^2 + 60^2 = 4000. SquareRoot(4000) = 63.25
![]()
At this point you can already tell the heading will be between 190 and 210ish.
Now you must solve for the angle that will give you the heading(or course).
![]()
First guy who whips out a scientific calculator in the cockpit does NOT get invited for beers after the flight.No idea how to do this mentally aside from just visualizing the picture and knowing that its between 190 and 210. But regardless heres the trig:
Pythagorean Theorm: A2 + B2 = C2
20^2 + 60^2 = 4000. SquareRoot(4000) = 63.25
![]()
At this point you can already tell the heading will be between 190 and 210ish.
Now you must solve for the angle that will give you the heading(or course).
![]()
Pythagorean Theorem (on flat Euclidean geometry) only works for triangles where one of the angles is 90 degrees i.e. a right triangle:
http://en.wikipedia.org/wiki/Pythagorean_theorem
For non-right triangles in flat Euclidean geometry, use Law of Cosines:
http://en.wikipedia.org/wiki/Law_of_cosines
Jussst sayyyin =)
First guy who whips out a scientific calculator in the cockpit does NOT get invited for beers after the flight.![]()