Alright, I confess that I've never learned why Va is lower in lighter airplanes than in heavier. I recently found the explanation that a lighter airplane will accelerate faster than a heavier aircraft with abrubt control input, thus pulling higher g's, and since aircraft are certified based on G loads, the lighter aircraft will need to slow down to ensure it will not be accelerated too quickly, thus pulling too many g's.
But, the lower weight of the aircraft allows it to pull more g's without overloading ths wings, right? I'm fairly certain that many planes can be considered regular or utility, based upon weight.
So what's the deal?
Thanks,
Mike
Mike:
The issue is complicated, because there are really two kinds of maneuvering speeds. The Va defined by the FAA is called
Design Maneuvering Speed. The intent of the speed is solely to protect the control surfaces from departing the aircraft if you deflect them at or below a certain speed. Here is an excerpt from Part 23, regarding the elevators:
Each horizontal surface and its supporting structure, and the main wing of a canard or tandem wing configuration, if that surface has pitch control, must be designed for the maneuvering loads imposed by the following conditions:
(a) A sudden movement of the pitching control, at the speed VA, to the maximum aft movement, and the maximum forward movement, as limited by the control stops, or pilot effort, whichever is critical.
(b) A sudden aft movement of the pitching control at speeds above VA, followed by a forward movement of the pitching control resulting in the following combinations of normal and angular acceleration:
etc.
There is similar language for the ailerons and the rudder. The loads imposed on these surfaces depends solely on calibrated airspeed. If these surfaces will stay attached at 95 knots max gross, then they will stay attached at any weight.
There is another type of maneuvering speed that you will find in aerodynamics books. This speed has nothing to do with control surfaces, but is solely a speed above which it is impossible to exceed the load factor limit of the airplane. This speed is defined as
Maneuvering speed = sqrt(n) * Vs
Where n is the load factor limit (such as 3.8) and Vs is the stall speed. The reason that the load factor limit cannot be exceeded is that you will stall the airplane before you reach it.
Many manufacturers have made Va and this aerodynamic maneuvering speed the same, but the FAA doesn't *require* it. In fact, they say that sqrt(n)*Vs is a lower limit, not a max limit. Here's what Part 23 says:
(1) VA may not be less than VS * sqrt(n) where -
(i) VS is a computed stalling speed with flaps retracted at the design weight, normally based on the maximum airplane normal force coefficients, C(na); and
(ii) n is the limit maneuvering load factor used in design
So Va can be set well above the speed that would protect the aircraft from stalling before it reached its load limit factor.
The FAA has defined another speed, Vo, which matches the aerodynamic maneuvering speed. Here's how it's defined:
§ 23.1507 Operating maneuvering speed.
The maximum operating maneuvering speed, VO, must be established as an operating limitation. VO is a selected speed that is not greater than VS times the square root of n established in § 23.335(c).
See the difference in definitions?
Now, your question also had to do with can a lighter airplane withstand a higher load factor limit when it's light. If the wings were the only consideration, then the answer is
yes, because the wings only see load, not load factor. However, there are many fixed weight items in the airplane, such as the engine, that may only be built to withstand some load factor times the weight of the component, and this limit will not change with overall changes in weight.