standard temperature decrease

I use standard, however it very rarely is standard.(Where I am anyways)
on a XC of mine I ended up in El Paso and my god, it is weird out there. Coming in at 8 thousand it was nice and -4, we land I look down and it's positive 5

talk about inversion
 
on a XC of mine I ended up in El Paso and my god, it is weird out there. Coming in at 8 thousand it was nice and -4, we land I look down and it's positive 5

talk about inversion
wait, it was backwards, we were at 4 positive land and it's -5.
 
Best thing to do is, before you do all the performance figures and all that good stuff just get a DUAT's report. Weather baloons don't lie. (For the most part)
 
Also, for the FAA written, they have a problem where you need to calculate the cloud base and for some reason they use Fahrenheit. Just use 4.4*/1000 for F.
 
Also, for the FAA written, they have a problem where you need to calculate the cloud base and for some reason they use Fahrenheit. Just use 4.4*/1000 for F.

Just a different way, convert to C:

(degrees F - 32) / 1.8 = degrees C

I always forget this formula, but for some reason I have no problem remembering the that it is + or - 32 and * or / by 1.8. So I just check myself with: 212 F (boiling point) - 32 = 180 / 1.8 = 100 C.
 
Not sure if this is correct but it has been explained to me that temperature decreases at 3 degree per 1,000 feet but dewpoint decreases 1 degree per thousand feet thus averaging it out to 2 degrees per thousand feet. Or something to that affect...I don't remember exactly but if anyone knows what I'm talking about feel free to correct me.
 
Not sure if this is correct but it has been explained to me that temperature decreases at 3 degree per 1,000 feet but dewpoint decreases 1 degree per thousand feet thus averaging it out to 2 degrees per thousand feet. Or something to that affect...I don't remember exactly but if anyone knows what I'm talking about feel free to correct me.

You are somewhat correct. The air expands as you climb, so the temperature cools, this is adiabatic, meaning there is no heat exchange. This rate is different for dry air and saturated air. Dry air's adiabatic lapse rate is 3*C/1000 and fully saturated air cools at 1*C/1000. Page 51 in the old "Aviation Weather" book by the FAA explains it.
 
Not sure if this is correct but it has been explained to me that temperature decreases at 3 degree per 1,000 feet but dewpoint decreases 1 degree per thousand feet thus averaging it out to 2 degrees per thousand feet. Or something to that affect...I don't remember exactly but if anyone knows what I'm talking about feel free to correct me.

Just to clarify, its 3C/1000ft dry adiabatic lapse and 1F/1000ft dew point lapse. so the base of the cumulus clouds is 4.4F/1000 ft or 2.4C/1000ft
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Don't confuse, and definately dont mix Celcius and Farenheit.
 
Just to clarify, its 3C/1000ft dry adiabatic lapse and 1F/1000ft dew point lapse. so the base of the cumulus clouds is 4.4F/1000 ft or 2.4C/1000ft
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Don't confuse, and definately dont mix Celcius and Farenheit.

It so much easier to use Celsius and kilometers, but that doesn't do a lot of good for flying. If you really want to know the environmental lapse rate, take a look at a Skew-T/Log-P chart.
 
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